The base BC of an equilateral triangle ABC lies on y axis. The coordinates of pt. C are (0,-3). If the origin is the mid pt. of the base BC, find the coordinates of the pt. A and B and hance find the area of the triangle.
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C is on y axis where (0,-3) is the point.
Origin is the m.p of BC
Then B=(0,3) and A=(5.2,0).
Therefore the ar(∆ABC)
=1/2bh
b= 6cm ,h=5.2cm.
=1/2(6*5.2)
=1/2(31.2)
=15.6cm²
Therefore the area of the ∆=15.6cm².
Hope its helpful!!
Origin is the m.p of BC
Then B=(0,3) and A=(5.2,0).
Therefore the ar(∆ABC)
=1/2bh
b= 6cm ,h=5.2cm.
=1/2(6*5.2)
=1/2(31.2)
=15.6cm²
Therefore the area of the ∆=15.6cm².
Hope its helpful!!
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