Question

the base of an isosceles triangle is 4/3 cm.the perimeter of the triangle is 4 integer 2/15cm.what is the length of either of the remaining equal sides?

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Answer 1

Answer:

$\huge\tt\underline\blue{answer}$

★let each of equal sides of an isosceles triangle be x cm.

★perimeter of a triangle=sum of all three sides

=>

$4 \frac{2}{15} = \frac{4}{3} + x + x$

=>

$\frac{62}{15} = \frac{4}{3} = 2 x$

=>

$\frac{62}{15} - \frac{4}{3} = \frac{4}{3} - \frac{4}{3} + 2x$

(subtracting 4/3 from both the sides)

=>

$\frac{62 - 20}{15} = 2x$

=>

$\frac{42}{15} = 2x$

=>

$\frac{42}{15 \times 2} = \frac{2x}{2}$

(dividing both side by 2)

=>

$\frac{7}{5} = x$

$x = 1 \frac{2}{5} cm$

hence,each equal side of an isosceles triangle is 1 integer 2/5cm.

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