Question

The binding energy of a deuterium nucleus is
about 1.115 MeV per nucleon. Then the mass
defect of the nucleus is about -

Answer 1

Answer:

2.2Mev

the binding energy per nuclear test 1.1 Mev the total binding energy 1H^2 +1H

1H^2 + 1H^2 gives 2HE^4

so the binding energy is equal to

2×1.115 = 2.2 Mev

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