The brakes applied to a car produce a negative acceleration of 10 m/s². If the car takes 5 s to stop
after applying brakes, calculate the distance covered by the car before coming to rest.
Answers
Answered by
9
v=u+at
0=x-50
u=50m/s
s=ut+1/2at2
s=50*5+1/2*10*25
s=250-125 (because accelaration is in opp direction)
distance=125m
0=x-50
u=50m/s
s=ut+1/2at2
s=50*5+1/2*10*25
s=250-125 (because accelaration is in opp direction)
distance=125m
Answered by
5
s=0×5+1÷2×10×5×5
s=0+5+5×5
s=125
s=0+5+5×5
s=125
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