Math, asked by arbindpathak1208, 5 months ago


The circumference of a circle is 88cm. Find the area of the sector whose central
angle is 45º.​

Answers

Answered by VinayGulati
8

Step-by-step explanation:

circumference of a circle = 2πr

88 = 2* 22/7 *r

r = 88 * 1/2 * 7/22 = 14cm

Area of sector = 45/360 * 22/7* 14* 14 = 77 cm^2

Answered by ashutosh456089
0

Answer:

88cm²

Step-by-step explanation:

2*22/7*r=88

2*22/7*r=88r=88*7/2*22

2*22/7*r=88r=88*7/2*22r=14

2*22/7*r=88r=88*7/2*22r=14the area of sector

2*22/7*r=88r=88*7/2*22r=14the area of sector 45/360*22/7*14*14

2*22/7*r=88r=88*7/2*22r=14the area of sector 45/360*22/7*14*141/8*22/7*14*14

2*22/7*r=88r=88*7/2*22r=14the area of sector 45/360*22/7*14*141/8*22/7*14*14=77cm²

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