The circumference of a circle is 88cm. Find the area of the sector whose central
angle is 45º.
Answers
Answered by
8
Step-by-step explanation:
circumference of a circle = 2πr
88 = 2* 22/7 *r
r = 88 * 1/2 * 7/22 = 14cm
Area of sector = 45/360 * 22/7* 14* 14 = 77 cm^2
Answered by
0
Answer:
88cm²
Step-by-step explanation:
2*22/7*r=88
2*22/7*r=88r=88*7/2*22
2*22/7*r=88r=88*7/2*22r=14
2*22/7*r=88r=88*7/2*22r=14the area of sector
2*22/7*r=88r=88*7/2*22r=14the area of sector 45/360*22/7*14*14
2*22/7*r=88r=88*7/2*22r=14the area of sector 45/360*22/7*14*141/8*22/7*14*14
2*22/7*r=88r=88*7/2*22r=14the area of sector 45/360*22/7*14*141/8*22/7*14*14=77cm²
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