Question

The co-ordinates of the vertices a, b of square abcd is (2, 0) and (0, 2) respectively. what is the area of the square abcd?

Answer 1

ABCD is a square , it means all sides of ABCD are equal.
Given, co-ordinate of A ≡ ( 2,0)
and co-ordinate of B ≡ (0,2)
Length of AB = $\bold{\sqrt{(2-0)^2+(0-2)^2}=\sqrt{4+4}=2\sqrt{2}}$
So, side length of square ABCD = length of AB = $\bold{2\sqrt{2}}$
∴ area of square = (side length)² = ($\bold{2\sqrt{2}}$)² = 8 sq unit