Question

The coach of a cricket team buys 7 bats and 6 balls for rupees 3800. Later, she buys 3 bats and 5 balls for rupees 1750. Find the cost of each bat and each ball. (Solve by substitution method)​

Answer 1

Answer:

500 for bat

50 for ball

Step-by-step explanation:

cost of 1 bat=x

cost of 1 ball=y

therefore atq= 7x+6y=3800------1

and, 3x+5y=1750

by substitution method-

35x+30y=19000

18x+30y=10500

--------------------------

17x=8500. (subtract)

x=500

y=50

mark brainliest

Answer 2

let the cost of 1 bat be₹X

cost of 1 ball =Y

7x+6y=3800----------(i)

3x+5y=1750-----------(ii)

from (i) 7x+6y=3800

$\: \: \: \: \: \: \: 7x = 3800 - 6y$

$x = \frac{3800 - 6y}{7}$

$substituting \: x = \frac{3800 - 6y}{7} \: in \: equation(ii)$

$\implies \: 3( \frac{3800 - 6y}{7} ) + 5y = 1750$

$\implies \: \frac{11400 - 18y}{7} + 5y = 1750$

$\implies \: \frac{11400 - 18y}{7} + 35y = 1750$

$\implies \: \frac{11400 + 17y}{7} = 1750$

$\implies \: 11400 + 17y = 1750 \times 7$

$\implies \: 11400 + 17y = 12250 \\ \implies \: 17y = 12250 - 11400$

$\implies \: 17y= 850$

$\implies \: y = \frac{850}{17}$

$\implies \: y = 50$

$putting \: y \: = 50 \: in \: equation \: (iii)$

$x = \frac{3800 - 6(50)}{7}$

$\implies \: x = \frac{3800 - 300}{7}$

$\implies \: x = \frac{3500}{7}$

$\implies \: x\: = 500$

$\therefore \: cost \: of \: 1 \: bat = 500 \\ cost \: of \: 1 \: ball \: = 50$