The coordinates of the centroid of triangle PQR with vertices P (-1,0),Q (5,-2)R (8,2) are
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The coordinates of the centroid of the triangle PQR is (4, 0)
Formula:
If (x₁, y₁), (x₂, y₂) and (x₃, y₃) be the coordinates of the vertices of a triangle, then the coordinates of the centroid of the triangle be
( (x₁ + x₂ + x₂)/3, (y₁ + y₂ + y₃)/3 )
Solution:
The given triangular PQR has vertices P (- 1, 0), Q (5, - 2) and R (8, 2).
∴ using the above formula, we get the coordinates of the centroid of the triangle to be
( (- 1 + 5 + 8)/3, (0 - 2 + 2)/3 )
i.e., ( 12/3, 0/3 )
i.e., (4, 0)
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