Math, asked by Krishna11123, 1 year ago

the diameter of a roller is 84cm and it's length is 120cm. it takes 500complete revolutions to move once over to level a play ground. Find the area of the playground in square metre

Answers

Answered by nani234
2
r=0.42m
h=1.2m
CSA=2πrh
= 3.168m²
if takes 500 revolutions
= 3.168*500
=1584m²

Krishna11123: thanks
Answered by SerenaBochenek
1

Answer:

\text{The area of playground is }1584m^2

Step-by-step explanation:

Given the diameter of a roller is 84 cm and it's length is 120 cm. It takes 500 complete revolutions to move once over to level a play ground.

we have to find the area of playground

Diameter of roller=84 cm

Radius=42 cm=0.42 m

Height=120 cm=1.2 m

Curved surface area=2πrh=2(3.14)(0.42)(1.2)

                                 = 3.168 square meter

Now given if takes 500 revolutions   to move once over to level a play ground.

\text{Total area=}3.168\times 500

                         =1584m^2

\text{The area of playground is }1584m^2

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