the digit in the tens place of a two digit number is 3 times of that in the ones place if the digits are reversed the new number will be 36 less than the original number find the number
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let the digit be xy. given x=3y and no.=10x+y....
=30y+y
now digits are reversed
new no.=10y+3y
13y=31y-36
18y=36
y=2
that means.. no=62
=30y+y
now digits are reversed
new no.=10y+3y
13y=31y-36
18y=36
y=2
that means.. no=62
Answered by
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Let unit's digit = x
Let ten's digit = y
The number = 10y + x
When the number is reversed = 10x + y
Y = 3x
10y + x -(1ox - y) = 36
10y + x - 10x - y = 36
9y - 9x = 36
9(y - x) = 36
y - x = 36/9
= 4
3x - x = 4
2x = 4
x = 4/2
= 2
y = 3*2
= 6
Number =62
Let ten's digit = y
The number = 10y + x
When the number is reversed = 10x + y
Y = 3x
10y + x -(1ox - y) = 36
10y + x - 10x - y = 36
9y - 9x = 36
9(y - x) = 36
y - x = 36/9
= 4
3x - x = 4
2x = 4
x = 4/2
= 2
y = 3*2
= 6
Number =62
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