The elastic limit of a steel cable is 3.0xx10^(8) N//m^(2) and the cross-section area is 4 cm^(2). Find the maximum upward acceleration that can be given to a 900 kg elevator supported by the cable if the stress is not to exceed one - third of the elastic limit.
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Maximum upward acceleration is 34.64 m/s²
Elastic limit of steel cable = 3.0×10`8N/m² (Given)
Cross section area = 4 cm² (Given)
Mass of elevator = 900 kg (Given)
According to the formula -
m ( g + a )/ A = 1/3⊂
a = ⊂A/3
= 3 × 10`8 . 4 × 10`-4/ 3 × 900 - 9.8
= 34.64
Thus, the maximum upward acceleration is 34.64 m/s²
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