Physics, asked by devashish6933, 11 months ago

The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths, λ₁/λ₂, of the photons emitted in this process is :
(A) 20/7 (B) 7/5
(C) 9/7 (D) 27/5

Answers

Answered by Itzcutegirl0

Answer:

The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths, λ₁/λ₂, of the photons emitted in this process is :

(A) 20/7

(B) 7/5

(C) 9/7 ✔✔

(D) 27/5

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The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths, λ₁/λ₂, of the photons emitted in this process is : (A) 20/7 (B) 7/5 (C) 9/7 (D) 27/5

Answers

(C) 9/7 ✔✔

The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths, λ₁/λ₂, of the photons emitted in this process is :
(A) 20/7 (B) 7/5
(C) 9/7 (D) 27/5