Question

The electronic configuration of some elements are given below:
a. 1s2, 2s2, 2p6, 3s2
b. 1s2, 2s2, 2p6
C. 1s2, 2s2, 2p2
d. 1d2, 2s2, 2p6, 3s1
e. 1s2, 2s2, 2p5 .
Answer the following questions:
i. Name the elements.
ii. Which of these have the lowest lonization enthalpy?
iii. Which is a halogen?
iv. Which is an alkali metal?
v. Which is an inert gas?​

Answer 1

Answer:

i. a - Magnesium

  b - Neon

  c - Carbon

  d - Sodium

  e - Fluorine

ii. Sodium

iii. Fluorine

iv. Sodium

v. Neon

Answer 2

Answer:

Given :

Electronic configuration of some elements are as :

a . 1 s² , 2 s² , 2 p⁶ , 3 s²

b . 1 s² , 2 s² , 2 p⁶

c . 1 s² , 2 s² , 2 p²

d . 1 s² , 2 s² , 2 p⁶ , 3 s¹

e . 1 s² , 2 s² , 2 p⁵

1 . Names of elements are Magnesium , Neon , Carbon , Sodium and Fluorine respectively .

2. Sodium has he lowest lonization enthalpy.

3. Fluorine is halogen.

4 . Sodium is alkali metal.

5 . Neon is an inert gas.