The enthalpy of solution of sodium chloride is 4 kJ mol⁻¹ and its enthalpy of hydration of ions is –784 kJ mol⁻¹. Then the lattice enthalpy of NaCl (in kJ mol⁻¹) is
(a) + 788
(b) + 4
(c) + 398
(d) + 780
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Answer:a)788
Explanation◇:H(soln)=◇H(latice energy)+◇H(hydration)
4= -784+◇H(latice)=788
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