Science, asked by patelhemangi, 9 months ago

The enzyme RNase A requires the formation of four disulphide bonds amongst its eight cysteine residues. If this is entirely
a random phenomenon, the probability that the first correct disulphide bond will be formed is 1/7. Following the same
logic, what is the probability of formation of all four correct disulphide bonds?
Solution​

Answers

Answered by bibha2576
0

Answer:

The enzyme RNase A requires the formation of four disulphide bonds amongst its eight cysteine residues. If this is entirely

a random phenomenon, the probability that the first correct disulphide bond will be formed is 1/7. Following the same

logic, what is the probability of formation of all four correct disulphide bonds?

Solution​

Explanation:

The enzyme RNase A requires the formation of four disulphide bonds amongst its eight cysteine residues. If this is entirely

a random phenomenon, the probability that the first correct disulphide bond will be formed is 1/7. Following the same

logic, what is the probability of formation of all four correct disulphide bonds?

Solution​

Answered by archiraj215
0

Answer:

explanation given in image

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