The eqivalent mass of a divalent metal is 10 g eq^-1.The molar mass of its anhydrous oxide is....................
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Hola mate....Here is your answer...
Equ. Mass = molar mass / valency
So molar mass of 1 mol. of that metal = 2 × 10 = 20 gm
Divalent metal forms an oxide like MO
Molar mass of that compound = 20 + 16 = 36 gm.
Hope u understood ^_^
Equ. Mass = molar mass / valency
So molar mass of 1 mol. of that metal = 2 × 10 = 20 gm
Divalent metal forms an oxide like MO
Molar mass of that compound = 20 + 16 = 36 gm.
Hope u understood ^_^
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