The equation of the circle which passes through the point (4, 5) and has its centre at (2, 2) is ________________ .
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(x-2)^2+(y-2)^2=r^2
put the point (4,5) in this equation, you will get the value of r^2=13.
put the point (4,5) in this equation, you will get the value of r^2=13.
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