Question

The equation of the line parallel to the line 2x-3y=1
and passing through the middle point of the line segment joining the points (1, 3) and (1, - 7), is
A) 2x-3y+8=0 B) 2x-3y=8 C) 2x-3y+4=0 D) 2x-3y=4

Answer 1

the midpoint of the line segment is (1+1/2,3-7/2)
= (1,-2)
the equation of the line parallel to the line 2x-3y = 1 is of the form 2x-3y = k
since it passes through (1,-2)
2(1)-3(-2) = k
k = 8
hence the required equation is 2x-3y=8