Question

The equations of two sides of a square whose area is 25 sq.units are 3x-4y=0 and 4x+3y=0.The equation of the other two sides of the square are
1) 3r-4y+ 25 = 0, 4x + 3y + 25 = 0
2) 3x - 4y + 5 = 0, 4r + 3y + 5 = 0
3) 3.x - 4y + 5 = 0, 4r + 3y + 25 = 0
4) 3x - 4y = 0, 4r + 3y = 0
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Answer 1

Answer:

Step-by-step explanation:

correct ans is option one

a=25 sq.unts

a square=25

a=5 units

3x-4y=0

[0,0]

3x-4y=0

4y=3x

y=3x/4

it is parallel

y=3/4 x+c

sincea=5

parallel distance=y-3/4 x-c=0=5

0-0-5/root 1+9/10=5

c=5*5/4

c=25/4 or -25/4

on other side

y=3/4 x + or-2/4

3y +4x=0

3y=-4x

y=-4x/3

since to make it parallel

y=-4/3 x+c

perpendicular distance =y+4/3 x-c=0=5

0-0-c/root 1+16/9=5

c=5*5/3

c=25/3 or -25/3

therefore

-4x/3 +or- 25/3

Answer 2

Answer:

Step-by-step explanation:

-25/3