Question

the external length, breadth and height of a wooden box open at the top are 10 CM, 8 CM and 5cm respectively. If the total thickness of the wood is 1 CM, the total surface area of the box is? ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Outer dimensions of the box are 10,8,5 respectively.

The thickness of wood is 1cm.

∴ inner dimensions are 10−2,8−2 and 5−1 i.e., 8 cm., 6 cm. and 4 cm.

∴ outer surface area =10×8+2×5(10+8)

=80+180=260cm

2

and inner surface area =8×6+2×4(8+6)

=48+112=160cm

2

and Area of top =lb−(l−2)(b−2)=10×8−8×6=32

So total SA=260+160+32=452 sq. cm

Step-by-step explanation: