Question

the figure shows a rectangle ABCD were the diagonals AC and BD intersect at E. GIVEN THAT BEC = 52 FIND ADB and ACD

Answer 1

Answer:

Since AC=BD and P bisects them

So, PD=PA

So, ∠PAD=∠PDA=x (Let)

In △PDA

∠APD+∠PDA+∠DPA=180

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So, ∠PAD=∠PDA=64

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Similarly Since ∠DPA=∠CPB (vertically opposite angles)

∠PCB=∠PBC=64

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So, ∠ACB=64

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Now, ∠B=90

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(angle of rectangle)

∠CBD+∠PBA=90

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64

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+∠PBA=90

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∠PBA=26

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So, ∠ABD=26

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Step-by-step explanation:

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