Question

the first three terms of an AP are 3y-1,3y+5and 5y+1 respectively.find the value of y

Answer 1

Answer:

Step-by-step explanation:

3y+5-(3y-1) = 5y+1-(3y+5)

6 = 2y-4

Y= 5

So the three terms are 14,20,26

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Answer 2

The value of y from the given question is 5.

Step-by-step explanation:

Given:

The first three terms of an AP are 3y-1, 3y+5 and 5y+1 respectively.

To find:

Find the value of y

Solution:

In an AP,

Generally t2 – t1 = t3 – t2

Here t1 = 3y – 1

t2 = 3y + 5  

t3 = 5y + 1

t2 – t1 = t3 – t2

3y + 5 – (3y – 1) = 5y + 1 – (3y + 5 )

6 = 2y -4

2y = 6 + 4

2y = 10, y = 5

The value of y is 5.

To know more:

The sum of the first three terms of an A.P is 33. If the product of first and the third and the third term exceeds the second term by29, find the A.P

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