Question

the floor of a budding is made up of 2550 tiles which are in the shape of rhombus. if diagonals of each tile are of length 20cm and 28cm, find. the cost of polishing the floor at the rate of ₹25 per metre square,,.... ans me fast ​

Answer 1

Answer:

Given:-

Total no. of tiles =2550

Since the tiles are in the shape of rhombus and diagonals are of length 20cm and 28cm.

Therefore,

d

1

=20cm

d

2

=28cm

Area of one tile = Area of rhombus

As we know that area of rhombus is given as-

A=

2

1

×d

1

×d

2

Therefore,

Area of 1 tile =

2

1

×20×28=280cm

2

∴ Area of 2550 tiles =2550×280=714000cm

2

=71.4m

2

Given that the cost of polishing is Rs.25 per m

2

.

Therefore,

Cost of polishing the floor =25×71.4=Rs.1785

Hence the cost of polishing the floor is Rs.1785.

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Answer 2

Answer:

Given:-

Total no. of tiles =2550

Since the tiles are in the shape of rhombus and diagonals are of length 20cm and 28cm.

Therefore,

d

1

=20cm

d

2

=28cm

Area of one tile = Area of rhombus

As we know that area of rhombus is given as-

A=

2

1

×d

1

×d

2

Therefore,

Area of 1 tile =

2

1

×20×28=280cm

2

∴ Area of 2550 tiles =2550×280=714000cm

2

=71.4m

2

Given that the cost of polishing is Rs.25 per m

2

.

Therefore,

Cost of polishing the floor =25×71.4=Rs.1785

Hence the cost of polishing the floor is Rs.1785.

Step-by-step explanation:

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