The following figure shows a circle with center O if OP perpendicular to AB prove that Ap=BP use RHS congruency rule
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In triangle AOP and triangle BOP :
AO = BO(radius are equal)
Angle APO = angle BPO = 90°
OP = OP (common)
By RHS congruence rule,
Triangle AOP congruent to Triangle BOP.
Hence by cpct AP = BP.
Hope it's helpful to u.
AO = BO(radius are equal)
Angle APO = angle BPO = 90°
OP = OP (common)
By RHS congruence rule,
Triangle AOP congruent to Triangle BOP.
Hence by cpct AP = BP.
Hope it's helpful to u.
Shashi61:
Thank you so much
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