Question

the fourth vertex of D of a parallelogram ABCD whose three vertices are A(-2,3), B(6,7) and C(8,3) IS

Answer 1

Hi there!

♦ Given :-
Vertices of parallelogram ABCD

→ A = (-2, 3)
→ B = (6, 7)
→ C = (8, 3)
→ D = ?

♦ Constn. :- Joining A to C n' B to D

Diagonal AC = Diagonal BD

→ Co- ordinates from diagonal AC:-

O = [ 3, 3 ]

→ Co- ordinates from diagonal BD:-

O = [ 6 + x / 2, 7 + y / 2 ]

Thus,

6 + x / 2 = 3

6 + x = 6

x = 0

n'

7 + y / 2 = 3

7 + y = 6

y = -1

Therefore,
Co- ordinates of D = (x, y) = (0, -1)

hope it helps! :)

Answer 2

hope it helps.
thank you.