. the horizontal range of a projectitle is 4/3 times its maximum height. Find the angle of projectitle
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1
4H = Rtanθ
4H = (4H/3) tanθ
3 = tanθ
Angle of projectile,θ = (3.tan⁻¹)
4H = (4H/3) tanθ
3 = tanθ
Angle of projectile,θ = (3.tan⁻¹)
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0
4/3)H = R
(4/3)(u^2sin^2Ф/2g) = u^22sinФcosФ
tanФ=3
Ф = tan inverse 3
(4/3)(u^2sin^2Ф/2g) = u^22sinФcosФ
tanФ=3
Ф = tan inverse 3
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