Question

The k.e. and p.e. of a particle executing SHM with amplitude A will be equal when its displacement is

Answer 1

kinetic energy in shm

= 1/2 kx^2

potential energy in shm

= 1/2 k (a^2-x^2)


equalise them

you will get

x^2 = a^2-x^2

x^2 = a^2/2

x = a/root2

HOPE IT WILL HELP YOU

Answer 2

Hello buddy,

# Answer-

x = A/√2

# Solution-

We have to find the displacement x for which kinetic energy = potential energy

Total energy (E)= potential energy + kinetic energy.

Hence

potential energy = kinetic energy = (1/2) E = (1/2)(1/2) kA^2

where, k is force constant and A is amplitude.

Next, potential energy at displacement x is(1/2)kx^2.

Therefore

(1/2) kx^2 = (1/2)(1/2) kA^2

x^2 = A^2 / 2

x=A/√2

Hence, KE=PE when displacement from mean is A/√2 cm.

Hope it helps...