Question

The largest number which when divided by 245 and 1029leaves a remainder 5 in each case is

Answer 1

$\huge\mathfrak{Solution:-}$

Given numbers=245,1029

Remainder=5

New numbers=245-5=240, 1029-5=1024

Largest number=HCF of numbers

HCF=(240,1024)

By Euclid's division lemma

1024=240×4+44

240=44×5+20

44=20×2+4

20=4×5+0

HCF=4

$\huge\mathfrak\boxed{Answer=4}$