Question

the lenght of the rectangle is 8 m less than twice its breadth.If the perimeter of the rectangle is 56m. Find its dimensions

Answer 1

hopefully this answer will help you out...thanq

Answer 2

Given :

• The lenght of the rectangle is 8 m less than twice its breadth.
• Perimeter of the rectangle is 56m.

To find :

• Dimensions of the rectangle =?

Formula Used :

• Perimeter of the rectangle = 2(length + breadth)

Step-by-step explanation :

Let, the breadth of the rectangle be, x.

Then, the length of the rectangle be, 2x.

It is Given that,

The lenght of the rectangle is 8 m less than twice its breadth.

So, length of the rectangle = 2x - 8

As We know that,

Perimeter of the rectangle = 2(length + breadth)

Substituting the values in the above formula, we get,

56 = 2(x + 2x - 8)

56 = 2 (3x - 8)

56 = 6x - 16

6x = 56 + 16

6x = 72

x = 72/6

x = 12.

Therefore, We got the value of, x = 12.

Hence,

Breadth of the rectangle, x = 12 m.

Length of the rectangle, 2x - 8 = 2 × 12 - 8 = 16 m.