Question

The length, breadth and height of a cuboidal water tank are 7m, 6m and 15m respectively. If 8400 liters of water is pumped out of the water tank, find the fall in the water level in the water tank.

Answer 1

0.2 m fall in height of water

Answer 2

$\textbf{\huge\underline{\underline\red{solution} : - }} \\ \\ \bold{\underline\purple{here \: we \: know}} \\ \\ \red{1.} \bold \blue{ \: length \: (l)\: of \: cuboidal \:water \: tank \: is \: 7 \: m .} \\ \red{2.} \bold \blue{ \: breadth \:( b)\: of \: cuboidal \: water\: tank \: is \: 6 \: m.} \\ \red{3.} \bold \blue{ \: height \: (h)\: of \: cuboidal \: water \: tank \: is \: 15 \: m.} \\ \red{4.} \bold \blue{ \: 8400 \: litres \: of \: water \: pumped \: out \: from } \\ \: \: \: \: \bold \blue{water \: tank.} \\ \\ \underline\bold\red{ \: To \: find \: \: fall \: of \: water \: level \: in \: water \: tank.} \\ \\ \underline\bold\red{ \: we \: use \: formula : - } \\ \\ = > \underline\bold\purple{volume \: of \: cuboid } = \bold\red{l \times b\times h} \\ \\ = > \underline\bold\purple{volume \: of \: cuboid } = \bold\red{7 \times 6\times 15} \\ \\ = > \underline\bold\purple{volume \: of \: cuboid } = \bold\red{630 \: {m}^{3} } \\ \\ \underline\bold\red{ \: we \: know \: } \: \: \fbox\bold\pink{ \: 1 \: {m}^{3} = \: 1000 \: litre \: } \\ \\ \underline\bold\blue{ \: hence} \\ \\ \bold\purple{\:630 \: {m}^{3} = 630 \times 1000 = 630000 \: litre} \\ \\ \underline \bold\blue{now} \\ \\ \underline\bold\purple{fall \: of \: water \: level \: in \: water \: tank} \\ = \: \: \: \bold\blue{(water \: in \: water \: tank \:) } \\ \: \: \: - \bold\orange{ \: (\: 8400 \: litre water \: pumped \: out)} \\ \\ \bold\purple{fall \: of \: water \: level... =( 630000 \: - 8400 \:) litre} \\ \\ \bold\purple{fall \: of \: water \: level... = 621600 \: litre} \\ \\ </p><p> \underline \bold \red{Hence \blue{\: 621600 \: litre \: }water \: remain \: in \:water \:} \\ \underline \bold \red{ tank \: after\blue { \: 8400 \: litre \: } \: of \: water \: pumped \: out.}$