Question

The length of a rectangle is 7 m more than its breadth. If its perimeter is 50 m, find the length

and breadth of the rectangle.

Answer 1

Perimeter of the rectangle=50m
sum of the measures length and breadth=50÷2=25
Now, let the measure of breadth be x 
measure of length be x+7
therefore, x+7+x=25
=2x+7=25
= 2x=25-7
=x=18÷2
=x=9
Now length of the rectangle=9+7=16
breadth of the rectangle=9

Answer 2

imagine that the breadth of the rectangle is a m.
the length of the rectangle is 7 m more than its breadth so the length is a+7 m
the perimeter of the rectangle is 50 m
According to the question,
$2(a + 7 + a) = 50 \\ or \: \:4a + 14 = 50 \\ or \: \: 4a = 36 \\ or \: \: a = 9m$
so the breadth of the rectangle is 9m
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