Question

The length of a rectangular wooden board is thrice its width .if the width of the board is 120 cm ,find the cost of framing it at the rate of $5 for 20cm

Answer 1

Length = 3x

Breadth = x = 120cm

Therefore,

Length = 120 x 3

= 360cm

Perimeter = 2 x ( 120 + 360 )

= 2 x 480

= 960

Cost for framing = 960/20 x 5$

= 240$

Answer 2

The cost of framing the rectangular wooden board is $ 240.

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Let's understand a few concepts:

To solve the given problem we will take the help of the following formula for the perimeter of a rectangle:

$\boxed{\bold{Perimeter\:of\:rectangle = 2 \times (Length + Width)}}$

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Let's solve the given problem:

The width of the rectangular wooden board = 120 cm

The rectangular wooden board's length is thrice its width, so we get

The length of the rectangular wooden board = 3 × 120 = 360 cm

Therefore,

The perimeter of the rectangular wooden board is,

= 2 × [length + width]

= 2 × [360 + 120]

= 2 × 480

= 960 cm

Now,

If the cost of framing 20 cm of the wooden board = $ 5

The cost of framing 1 cm of the wooden board = $\ \:\frac{5}{20} = \ \: \frac{1}{4}$

Then,

The cost of framing the 960 cm rectangular wooden board is,

= $960 \times \frac{1}{4}$

= $\bold{\ \:240}$

Thus, the cost of framing it at the rate of $5 for 20cm is $ 240.

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