Question

The length of shadow of a pole 50 m high is 50/√3 m. find the sun’s altitude.

Answer 1

LINE OF SIGHT: The line of sight is a line drawn from the eye of an observer to the point in the object viewed by the observer.

ANGLE OF ELEVATION: The angle of elevation of an object viewed is the angle formed by the line of sight with the horizontal , when it is above the horizontal level.

ANGLE OF DEPRESSION:The angle of depression of an object viewed is the angle formed by the line of sight with the horizontal , when it is below the horizontal level.

•Angle of elevation and depression are always acute angles.
•If the observer moves towards the perpendicular line(Tower/ building) then angle of elevation increases and if the observer move away from the perpendicular line(Tower/ building) angle of elevation decreases.

SOLUTION:

GIVEN:
BC = 50 m(the height of the pole)

Let AB=  50/√3 m be length of the Shadow of the pole.

In ∆ABC ,
tan θ = BC / AB = P/ B
tan θ = 50 / 50/√3
tan θ = 50 × (√3/50) = √3
tan θ = √3 = tan 60°

θ = 60°

Hence, the sun’s altitude is 60°

HOPE THIS WILL HELP YOU...

Answer 2

Answer:

SAME AS ABOVE

Step-by-step explanation: