Question

the marked price of a computer is rupees 22000.after allowing a 10% discount, a dealer still makes a profit of 20% .find the cost of a computer

Answer 1

Profit = selling price - cost price

let the cost price be c
The selling price:

= 10% discount
= discounted price = 100%(marked price) - discount (10%) = 90%
= 90%/100% × 22000
= 0.9 × 22000
= rs. 19800
This discounted price is the selling price.

Therefore profit = 19800 - C

% profit = profit/ cost price ×100%

= 19800-c/ c ×100% = 20%

= 100(19800-c)/c = 20

= 1980000 - 100c = 20c

= 120c = 1980000

= c = 1980000/120

c = Rs. 16500


Therefore the cost price of the computer is Rs. 16500

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Answer 2

M.P.=22000

discount%=10%

profit%=20%

Discount=10%of M.P.

10/100×22000

=2200

S.P= M.P. -discount

=22000-2200

=19800

Let CP be X

profit=20% of CP

=20/100× X

=₹x/5

$\therefore{CP+profit=X+\frac{X}{5}}$

=₹6x/5

$\therefore\frac{6x}{5}=19800$

$\implies{X=3300×5=16500}$

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