Question

the mass of % of an organic compound is c=57.8% h=3.6% and rest is oxygen. the molecular weight of compound is 166. what is molecular formula?

Answer 1

Given:

C= 57.8 %
H = 3.6 %
--------------
61.4 %
Thus O = 38.6%

Molecular weight = 2
×
Vapour density
= 2
×
83
= 166 u
Thus,


Mass of C =
57.8100
× 166
=95.948 g
No. of C atoms =
95.94812
(12 = mass of 1
C atom)
=7.99 ~ 8 C atoms.
Mass of H =
3.6
100
×166 = 5.976 gms
= 5.976 ~ 6 atoms.
Mass of O =
38.6100
× 166
=64.076 g
No. of O atoms =
64.07616
=4 atoms.


Thus the formula will be C8H6O4

Answer 2

Answer:

Explanation:

Given:

C= 57.8 %

H = 3.6 %

--------------

61.4 %

Thus O = 38.6%

Molecular weight = 2

×

Vapour density

= 2

×

83

= 166 u

Thus,

Mass of C =

57.8100

× 166

=95.948 g

No. of C atoms =

95.94812

(12 = mass of 1

C atom)

=7.99 ~ 8 C atoms.

Mass of H =

3.6

100

×166 = 5.976 gms

= 5.976 ~ 6 atoms.

Mass of O =

38.6100

× 166

=64.076 g

No. of O atoms =

64.07616

=4 atoms.

Thus the formula will be C8H6O4