The maximum number of electron in an atom which can have (n+l)=4
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electrons having n=3 and having p subshell
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Hey there!
Given,
n + l = 4
where,
l = angular momentum quantum number
n = Principle quantum number
From Energy level of electrons we know,
l ≤ n - 1
Satisfying this condition,
The values of n and l will be 3,1 and 4,0 respectively.
Now:
Case I:
n = 3
l = 1
so, here these represents 3p subshell.
Hence, maximum no. of electrons = 6
Case II:
n = 4
l = 0
so, here these represents 4s subshell.
Hence, maximum no. of electrons = 2.
Therefore, from case I and II:
Total no. of electrons = 6 + 2 = 8
We know,
Electrons with same pin = 8 / 2 = 4.
Hope It Helps You!
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