the number of consecutive zeros in 2^3×3^4×5^4×7 plss answer fast
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We can write 2³×3⁴×5⁴×7 as 2³×5³×3⁴×5×7
2³×5³ = 1000
So the above number becomes 1000×3⁴×5×7
Now, any combination of 3, 5 and 7 cannot give a 0 in units place. So the only 0s in the number are due to 1000. So, there are three consecutive 0s.
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Here's your answer...
We can write 2³×3⁴×5⁴×7 as 2³×5³×3⁴×5×7
2³×5³ = 1000
So the above number becomes 1000×3⁴×5×7
Now, any combination of 3, 5 and 7 cannot give a 0 in units place. So the only 0s in the number are due to 1000. So, there are three consecutive 0s.
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aaa140:
from where 1000 came
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