Question

the number of oxygen molecules present in 1 litre flask at a pressure of 101.325 into 10 ^ - 12 of kilopascals under temperature 101.325 kelvin is ​

Answer 1

Answer:

n=

RT

PV

....(i)

P=

760

7.6×10

−10

=10

−12

atm

V=1 L,T=273 K,R=0.0821 L atm K

−1

mol

−1

From eq. (i) n=

0.0821×273

10

−12

×1

Number of molecules =n×6.023×10

23

=

0.0821×273

10

−12

×6.023×10

23

=2.68×10

10