the number of solution of the pair of equation 2 x minus 3 Y - 9 equal to zero and 4 x + 6 Y - 18 equal to zero is
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Answered by
1
2x - 3y - 9= 0
4x + 6 y - 18 = 0
It is clear that, a1/a2 ≠b1/b2
No. of solution is one
For the solution, we need to solve the pair of equations simultaneously.
Multiplying first equation by 2,
4x - 6 y -18 = 0
4x + 6y -18 = 0
Adding them,
8x = 18×2
x = 9/2 = 4.5
Substituting this value, in first equation,
9+3y-9 = 0
y = 0
So, intersection point = {4.5,0}
Hope it may help you !!!!!
4x + 6 y - 18 = 0
It is clear that, a1/a2 ≠b1/b2
No. of solution is one
For the solution, we need to solve the pair of equations simultaneously.
Multiplying first equation by 2,
4x - 6 y -18 = 0
4x + 6y -18 = 0
Adding them,
8x = 18×2
x = 9/2 = 4.5
Substituting this value, in first equation,
9+3y-9 = 0
y = 0
So, intersection point = {4.5,0}
Hope it may help you !!!!!
Answered by
1
2x-3y=9......(1)
4x+6y=18.....(2)
divide by 2in eq 2
so
2x+3y=9....(3)
from eq 1 and eq 2
2x-3y=9
2x+3y=9
................ .
4x=18
x=18/4
x=9/2
put the value of x in eq 1
2*9/2-3y=9
9-3y=9
3y=0
y=0
4x+6y=18.....(2)
divide by 2in eq 2
so
2x+3y=9....(3)
from eq 1 and eq 2
2x-3y=9
2x+3y=9
................ .
4x=18
x=18/4
x=9/2
put the value of x in eq 1
2*9/2-3y=9
9-3y=9
3y=0
y=0
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