Question

the ones digit of a 2 digit no is twice the tens digit . when a number formed by reversing the digit is added to the original number,the sum is 99 . Find the original number​

Answer 1

Answer:

Let the two digit number is xy

y is digit at unit's place

x is digit at ten's place

⇒ Number can be written as = 10x+y

According to the conditions : y=2x ___ (1)

and

(10x+y)+(10y+x)=99

⇒11x+11y=99

⇒x+y=9 (dividing by 11)

Now x+2x=9 (from (1))

⇒3x=9

⇒x=9/3=3

y=2x=6

⇒ Number is 36

MARK AS BRAINLIEST

Answer 2

let, the tens digit =x so, ones digit =2x

... number= 10x+2x=12x reverse number= 10x2x+X3D20×+x=21X

it is given that, 12x+21x=99

or 33x=99

so, x=3

original number=10x+2x

=30+6

=36 answer.