Question

The polynomial 2x³-kx²+7x-1 when divided by x-2, leaves the remainder 5. Then find the value of k. Pls help I am stuck on this question

Answer 1

Answer:

6 is the value

Step-by-step explanation:

Let f ( x ) = 2 x³ - k x² + 7 x - 1

If f ( x ) is divided be x - 2 ,

remainder = f ( 2 )

Hence :

f ( 2 ) = 5

⇒ 2 x³ - k x² + 7 x - 1 = 5

⇒ 2 . 2³ - k . 2² + 7 . 2 - 1 = 5

⇒ 16 - 4 k + 14 - 1 = 5

⇒ - 4 k = 5 - 13 - 16

⇒ - 4 k = - 24

⇒ k = - 24 / - 4

⇒ k = 6

Answer 2

$\mathbb{\red{Answer..}}$

Hey....

given::

x-2 is one of the zero..

hence,,

x- 2 = 0

x = 2..

SUBSTITUTE this value in prime equation..

2x³-kx²+7x-1

$2\times{2}^3-k\times2^{2}+7\times2-1$ = 5

$2\times8-4\timesk+14 -1$ = 5

16 - 4k +13 = 5

29 - 4k = 5

4k = 26

k = $6$

hence the required Value of k is,,,

k =$6$