Question

The population of a village increase by 7% every year . if the present population is 80000 then what will be the population after two years.

Answer 1

7% of 80000 is
7/100*80000=5600
80000+5600=85600next one year population
After a year population will beincrease 7% of 85600
7/100*85600=5992
85600+5992=91592

Answer 2

Answer:

The population after two years will be approximately 9159

Step-by-step explanation:

Present population  =  80000

We are given that The population of a village increase by 7% every year

So, we are supposed to find he population after two years.

Time = 2 years

R = 7%

Formula : $N(t)=N_0(1+r)^t$

N(t)is the population after t years

$N_0$is the initial population

Substitute the values

$N(t)=8000(1+0.07)^2$

$N(t)=9159.2$

Hence the population after two years will be approximately 9159