The product of two numbers each consisting of two digit is 4928 their lcm is 8 what is the smallest number of the two numbers
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4928/8 = 616
616/8 = 77
11*7 = 77
And also their hcf = 8
Means the two no are 88 and 56
So the smaller no is 56
616/8 = 77
11*7 = 77
And also their hcf = 8
Means the two no are 88 and 56
So the smaller no is 56
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