Question

The quantity y is partly constant and partly varies inversely as the square of x
(a) write down the relationship between x and y
(b) when x equals 1 y equals 11 and when x equals 2 and y equals 5 find the value of y when x equals 4

Answer 1

Answer:

(a) y=k+c/(x^2)

(b) y=2.125

Step-by-step explanation:

(b) 11=k+c.....1

   5=k+c/4.....2

using elimination method;

-3k=9

k=-3

substitute, k=-3, into equation 1

c-3=11

c=14

therefore; y=c/(x^2) -3

y=14/(16) -3

y=2.125

Answer 2

Answer:

I didn't got your explaination bro sry for that