The radius of a circle is 9cm and length of one of its chords is 14cm find the distance of the chord from tje centre
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the distance of the chord from the centre be x cm
given the radius of a circle is 9 cm
length of its chords is 14 cm
by Pythagoras theorem
81 = 49 + x^2
=> x^2 = 81 - 49
=> x = √(81-49)
=> x = √32 cm
given the radius of a circle is 9 cm
length of its chords is 14 cm
by Pythagoras theorem
81 = 49 + x^2
=> x^2 = 81 - 49
=> x = √(81-49)
=> x = √32 cm
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