the ratio between neutrons present in nitrogen atom and silicon atom with mass number of 14and 28
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Answered by
8
hey user !!!!!!
we know that
atomic mass of nitrogen:- 14
atoimc no of nitrogen::-7
atoimc mass of silicon ::- 28
atomic no of silicon::- 14
theirfore we know that no of neutrons = atomic mass -atomic no..
so ratio::- 7 : 14 = 1:2
the requried ratio = 1:2
we know that
atomic mass of nitrogen:- 14
atoimc no of nitrogen::-7
atoimc mass of silicon ::- 28
atomic no of silicon::- 14
theirfore we know that no of neutrons = atomic mass -atomic no..
so ratio::- 7 : 14 = 1:2
the requried ratio = 1:2
Answered by
3
we know that
atomic mass of nitrogen:- 14
atoimc no of nitrogen::-7
atoimc mass of silicon ::- 28
atomic no of silicon::- 14
theirfore we know that no of neutrons = atomic mass -atomic no..
so ratio::- 7 : 14 = 1:2
the requried ratio = 1:2
atomic mass of nitrogen:- 14
atoimc no of nitrogen::-7
atoimc mass of silicon ::- 28
atomic no of silicon::- 14
theirfore we know that no of neutrons = atomic mass -atomic no..
so ratio::- 7 : 14 = 1:2
the requried ratio = 1:2
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