The resistance of a metal wire of length 1m is 10 raised to 4 ohm at 20°C. If the diameter of the wire is 0.15mm, find the resistivity of the metal at that temperature.
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Answer:
resistivity will be 7.06×10^-4ohm meters
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Given that,
Length of metal wire (l) = 1 m
Resistance (R) = 10⁴ Ω
Temperature (T) = 20° C
Also given that, the diameter of the wire is 0.15 mm.
Diameter (d) = 0.15 mm = 1.5 × 10-⁴ m
Radius = Diamter/2 = (1.5 × 10-⁴)/2 = 7.5 × 10^5- m
We have to find the resistivity of the metal at that temperature.
Now,
R = p l/A
Here, R = resistance, p = rho (resistivity), l = length and A = area of cross-section
Also, Area = πr²
So,
R = p l/(πr²)
⇒ 10^4 = p (1)/(22/7 × 7.5 × 10^5- × 7.5 × 10^5-)
⇒ 10^4 = p (1)/(1.76 × 10^8-)
⇒ 10^4 × 1.76 × 10^8 = p
⇒ 1.76 × 10^12 = p
Therefore,
The resistivity of the metal at that temperature is 1.76 × 10^12 Ω m
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