Question

The speed of a scooter moving at a speed of 4m/s^2 is sometimes 20m/s. What will be its velocity after cutting the distance 1121 meter after that time?
Hint: use v^2 - u^2 = 2ax​

Answer 1

Hey!

Given,

a=4m/s²

u=20m/s

x=112m

putting these values in v²-u²=2ax, we get

v²-(20) ²=2×4×112

v²-400=896

v²=896+400

v²=1296

v=36m/s

So, Velocity after 112m = 36m/s.