The sum of the ages of a and b is 30 year after five years the age of a is 3 times more than b find their present ages
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Answered by
1
Present Age of "a" = 25 years
Present Age of "b" = 5 years
Let their Present age be x & y.
So, x + y = 30 _______(i)
After 5 years their are will be:
(x+5) & (y+5) years respectively.
Now, x+5 = 3(y + 5) ______(ii)
Solve the 2 equations, you'll get
x = 25 years
y = 5 years
Thankyou!!!
Present Age of "b" = 5 years
Let their Present age be x & y.
So, x + y = 30 _______(i)
After 5 years their are will be:
(x+5) & (y+5) years respectively.
Now, x+5 = 3(y + 5) ______(ii)
Solve the 2 equations, you'll get
x = 25 years
y = 5 years
Thankyou!!!
Answered by
1
Let the present age of a = x years
Let the present age of b = y years
According to question :
1st Condition :
x + y = 30 ...(1)
After Five years :
Age of a = x + 5
Age of b = y + 5
2nd Condition :
x + 5 = 3(y + 5)
x + 5 = 3y + 15
x + 5 - 3y - 15 = 0
x - 3y - 10 = 0
x - 3y = 10 ...(2)
From Equation (1) :
x + y = 30
x = 30 - y ...(3)
put the value of x in equation (2)
x - 3y = 10
(30 - y) - 3y = 10
30 - 4y = 10
4y + 10 = 30
4y = 30 - 10
4y = 20
y = 20 / 4
y = 5
put the value of y in equation (3)
x = 30 - y
x = 30 - 5
x = 25
The present age of a = x = 25 years
The present age of b = y = 5 years.
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Let the present age of b = y years
According to question :
1st Condition :
x + y = 30 ...(1)
After Five years :
Age of a = x + 5
Age of b = y + 5
2nd Condition :
x + 5 = 3(y + 5)
x + 5 = 3y + 15
x + 5 - 3y - 15 = 0
x - 3y - 10 = 0
x - 3y = 10 ...(2)
From Equation (1) :
x + y = 30
x = 30 - y ...(3)
put the value of x in equation (2)
x - 3y = 10
(30 - y) - 3y = 10
30 - 4y = 10
4y + 10 = 30
4y = 30 - 10
4y = 20
y = 20 / 4
y = 5
put the value of y in equation (3)
x = 30 - y
x = 30 - 5
x = 25
The present age of a = x = 25 years
The present age of b = y = 5 years.
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