the sum of the present age of mother and her daughter is 50 years. after 20 years mother's age will be twice her daughter's age at that time. find their present ages.
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Let mother's age=x
Daughter's age =50-x (sum of their ages is 50)
After 20 years,
Mother 's age=x+20
Daughter's age=50-x+20
=70-x
According to question,
x+20=2(70-x)
x+20=140-2x
2x+x=140-20
3x=120
x=120÷3
x=40
Hence mother's age is x that is 40 years
AND
Daughter's age is 50-x that is 10 years
Daughter's age =50-x (sum of their ages is 50)
After 20 years,
Mother 's age=x+20
Daughter's age=50-x+20
=70-x
According to question,
x+20=2(70-x)
x+20=140-2x
2x+x=140-20
3x=120
x=120÷3
x=40
Hence mother's age is x that is 40 years
AND
Daughter's age is 50-x that is 10 years
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